> are applied by PaVeReduce:
sorry, I meant PaVeOrder.
Cheers,
Vladyslav
Am 24.03.2015 um 23:38 schrieb Vladyslav Shtabovenko:
> Hi Cesar,
>
> C0 functions have certain symmetries in their arguments. Those
> are applied by PaVeReduce:
>
> f1 = PaVe[0, 0, {0, 0, m1^2}, {0, m2^2, m2^2}] // PaVeReduce
> f2 = (PaVe[0, 0, {m0^2, 0, m1^2}, {0, m2^2, m2^2}] // PaVeReduce) /.
> m0 -> 0
> PaVeOrder[f1 - f2]
>
> returns 0.
>
> Cheers,
> Vladyslav
>
>
>
>
> Am 24.03.2015 um 22:46 schrieb Cesar Lattes:
>> Hi,
>>
>> I found a very strange behaviour of the function PaVeReduce when one of the variables is much smaller than the others. It seems that I don't get the same reduce if I apply PaVeReduce before or after sending a specific variable to zero.
>>
>> For instance, if I try to compute:
>>
>> f1 = PaVe[0, 0, {0, 0, m1^2}, {0, m2^2, m2^2}] // PaVeReduce
>>
>> and
>>
>> PaVe[0, 0, {m0^2, 0, m1^2}, {0, m2^2, m2^2}] // PaVeReduce
>> f2 = % /. m0 -> 0 ,
>>
>> then I get a result which is not zero:
>>
>> f1 - f2 // Simplify
>>>>> 1/2 m2^2 (C0(m1^2,0,0,m2^2,0,m2^2)-C0(0,m1^2,0,m2^2,0,m2^2)) ,
>>
>> Am I doing something wrong? What is the good way to take this kind of limit?
>>
>> Thanks in advance.
>> C. L.
>>
>> PS. I'm using FeynCalc 8.2.0 and Mathematica 8.0 (for Students).
>>
>
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