We'll work with unexpanded operators:
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Notice that because det(U)=1, U=
, that is, there is no traceful part of
.
Abbreviation for
.
=UMatrix[U] is the solution to the eqation of motion.
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![(i ℵ (U '6 Overscript[ξ^( ), ->] · Overscript[σ, ->]))/f _ ϕ^(ó ) + U](../HTMLFiles/index_16.gif)
The lagrangian:
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Higher orders are dropped:
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Vanishing of total derivatives is used (surfaceRules is defined in the "Preliminaries" section):
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Rewrite using indices and simplify a bit:
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The functional derivative:
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With A ≡ a + b ÷¬öé, the condition
is equivalent to
, where a = A-![]()
. This stems from the fact that there is no traceful part of
.
Factor:
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![-(i DecayConstant[PseudoScalar[1], RenormalizationState[0]]^2 UTrace1[NM[NM[Adjoint[FieldDerivative[FieldDerivative[UMatrix[U][x], x, LorentzIndex[ρ1]], x, LorentzIndex[ρ1]]], UMatrix[U][x]] - NM[Adjoint[UMatrix[U][x]], FieldDerivative[FieldDerivative[UMatrix[U][x], x, LorentzIndex[ρ1]], x, LorentzIndex[ρ1]]] + NM[Adjoint[UMatrix[U][x]], UMatrix[UChi[]][x]] - NM[Adjoint[UMatrix[UChi[]][x]], UMatrix[U][x]], UMatrix[UGenerator[SUNIndex[i1]]]]])/(4 DecayConstant[PseudoScalar[1]])](../HTMLFiles/index_32.gif)
Finally, the equations of motion are found to read (well, the left-hand side,
to be set equal to 0)
![eqsU = NM[Adjoint[FieldDerivative[FieldDerivative[UMatrix[U][x], x, LorentzIndex[μ]], x, LorentzIndex[μ]]], UMatrix[U][x]] - NM[Adjoint[UMatrix[U][x]], FieldDerivative[FieldDerivative[UMatrix[U][x], x, LorentzIndex[μ]], x, LorentzIndex[μ]]] + NM[Adjoint[UMatrix[U][x]], UMatrix[χ][x]] - NM[Adjoint[UMatrix[χ][x]], UMatrix[U][x]] - 1/3 UTrace[NM[Adjoint[UMatrix[U][x]], UMatrix[χ][x]] - NM[Adjoint[UMatrix[χ][x]], UMatrix[U][x]]] UIdentityMatrix[]](../HTMLFiles/index_33.gif)
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Converted by Mathematica (July 10, 2003)