is functionalD is automatically in D-dimension

Name: myphuong le (email_not_shown)
Date: 10/23/06-08:33:39 PM Z


Hi,
I am trying to derive a Feynman rules for a 3 2-Lorentz-index fields in 5-dimension. From the reference (page 152), the FunctionalD seems to imply that it works automatically in D-dimension. When I try to specifically specify my lorentzIndex in the Lagrangian to be explicitly in D dimension, it wouldn't work. Here is the expressions I entered:

v3gt = QuantumField[h,{li1,li2},{1}].QuantumField[PartialD[li1],h,{li3,li4},{1}].QuantumField[PartialD[li2],h,{li3,li4},{1}]
v3gtD = ChangeDimension[v3gt,D];
g3Field = {QuantumField[h,{\[Mu],\[Nu]},{1}][k1],QuantumField[h,{\[Rho],\[Sigma]},{1}][k2],QuantumField[h,{\[Lambda],\[Tau]},{1}][k3]};
g3FieldD= ChangeDimension[g3Field,D];
t3gExpD = ExpandPartialD[v3gtD];
FunctionalD[t3gExpD,g3FieldD]

Looking into the FullForm of the Expression, seem like the expression in FunctionalD is happy only when it has LorentzIndex[mu] and not LorentzIndex[mu,D]. What do I need to do?
Thanks,
My Phuong



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