FeynCalc 3.0.1.3 For help do: ?FeynCalc
Copyright 1997 Mertig Research & Consulting (www.mertig.com)
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The three amplitude of -> -> is:
The momentum assignment is (as usual with FA): -> -> .
We use 't Hooft-Feynman gauge.
The Mandelstam variables are defined such that the fermion comes from the proton:
The amplitude squared is:
In the W CM frame:
This agrees with my hand calculations (notes: Total Cross Section) and C.-P.'s notes (Zeroth Order) and with CompHEP.
The averaging factors: initial state color and spin .
Taking away the initial state color and spin averaging factors and changing notation:
The three amplitude of -> -> is:
The momentum assignment is (as usual with FA): -> -> .
We use 't Hooft-Feynman gauge.
The Mandelstam variables are defined such that the fermion comes from the proton:
The amplitude squared is:
In the W CM frame:
The averaging factors: initial state color and spin .
Taking away the initial state color and spin averaging factors and changing notation:
The three amplitude of -> -> is (the -> -> process was deleted by hand):
The momentum assignment is (as usual with FA): -> -> .
We use 't Hooft-Feynman gauge. We made tha quark charge explicit.
The Mandelstam variables are defined in the standard way:
The amplitude squared is:
In the W CM frame:
This agrees with CompHEP.
The averaging factors: initial state color and spin .
Summation over colors has not been done yet.
Taking away the initial state color and spin averaging factors, making the quark charge and the color sum explicit and changing notation:
The three amplitude of -> γ γ is:
The momentum assignment is (as usual with FA): -> .
We use 't Hooft-Feynman gauge. The u quark charge is included by FA and taken made explicit.
This must still be summed over .
In the γγ CM frame:
This agrees with both Ohnemus and Owens and CompHEP.
The averaging factors: initial state color and spin and the identical final state particles factor .
To obtain the uanveraged amplitude square we take away the initial state color and spin averaging factors and the identical final state particles factor , make explicit the quark charges and the sum over colors ), and change notation:
This agrees with both Ohnemus and Owens and FC.
In Papageno the following is coded:
CONST=AEM**2*16.*PISQ
CONST1=QU4
CONST2=QD4
....
A4=CONST*2.*(U2+T2)/U/T/3.
A5=CONST*AL**2*11.**2/9**2.*2./4./8./8.*XMAT_PHOT(S,T,U)
WT=((SF(23)+SF(24))*CONST1+(SF(27)+SF(28))*CONST2)*A4/2.
1 +SF(9)*A5/2./16./PISQ
That is
After taking out the initial state color and spin averaging factors and the identical final state particles factor , and making the color sum explicit, for the amplitude square (before averaging) we obtain:
which agrees with both FC and CompHEP.
On page 56 they have
After taking out the initial state color and spin averaging factors and the identical final state particles factor , and making the color sum explicit, for the amplitude square (before averaging) we obtain:
There's a factor which I don't understand.
The box contribution to the amplitude of -> γ γ is:
The triangular contribution to the amplitude of -> γ γ is:
For all of the above diagrams:
- each diagram comes with a factor of 2, since the quark can run either in one or in the other direction in the loop,
- all six flavors can run around the loop.
We want to find out the normalization of the g g -> γ γ process with respect to the q -> γ γ process from Papageno.
In Papageno the following is coded:
CONST=AEM**2*16.*PISQ
CONST1=QU4
CONST2=QD4
....
A4=CONST*2.*(U2+T2)/U/T/3.
A5=CONST*AL**2*11.**2/9**2.*2./4./8./8.*XMAT_PHOT(S,T,U)
WT=((SF(23)+SF(24))*CONST1+(SF(27)+SF(28))*CONST2)*A4/2.
1 +SF(9)*A5/2./16./PISQ
That is
After taking out the initial state color and spin averaging factors and the identical final state particles factor , the factor (without the top quark) and making the factor from the color sum/traces explicit we obtain:
The factor (without and with the top quark) is
In RES.FOR:
- For H production we have:
- For γγ production we have:
In ResBos we have:
C Identical particle final state and spin average factors
& 1.d0/2.d0/2.d0/2.d0*
C Effective matrix element
& 2.d0*(gWeak*sWeak)**4/(16.0*Pi**2)*
CsB t and b quark masses are non-zero in loop:
& GGAA(sH,tH,uH)*(SigS+SigY(0))
The three amplitude of -> Z Z is:
The momentum assignment is (as usual with FA): -> .
We use 't Hooft-Feynman gauge. The u quark charge is included by FA and taken made explicit.
This must still be summed over .
In the γγ CM frame:
This agrees with both Ohnemus and Owens and CompHEP.
The averaging factors: initial state color and spin and the identical final state particles factor .
We make the initial state color and spin averaging factors and the identical final state particles factor , and the sum over colors ) explicit ((the quark charges )), and change notation:
This agrees with Ohnemus and Owens.
Notes:
Compared to the process, in the amplitude square of there's an extra factor:
This means: to obtain the resummation formula for from the resummation formula for we have to inclue an extra numerical factor, include extra quark charges , and include an extra factor of .
An extra numerical factor comes from the identical particle final state, which means that the overall extra factor (for compared to ) is 2.
(Note that the initial state is the same, which means that the color and spin averaging factors are the same for both process.)
In RES.FOR:
- the quark charges are adjusted.
In ResBos:
- for γγ: | *2=8is programmed, | |
- for -> ö½ö½': | is programmed. |
Compared to the symmetric part of the process in the amplitude square of there's an extra factor:
This means: to obtain the resummation formula for from the resummation formula for we have to set -> , inclue an extra numerical factor, get rid of the W propagator, include the quark charges, replace with , and include an extra factor of .
Extra numerical factor coming in from the different averaging:
The numerical factors combined give an overall extra factor of:
Based on Papageno the ratio of the weights of the g g -> γ γ and q -> γ γ processes is:
From here we see the differences:
- the (unaveraged, un-color-summed) amplitude square (not including the couplings or quark charges),
- the initial color averaging factors,
- the color factors,
- the couplings.
The factor is:
The factor then should be:
The three amplitude of -> Z Z is:
The momentum assignment is (as usual with FA): -> .
We use 't Hooft-Feynman gauge.
For simplicity we neglect the Z mass
This must be summed over .
Ohnemus and Owens (PRD43,3626(1991)) has in Eq.(4) (for f = u and after taking )